Question 4 Graph the solution to the system: Area 1 Area 2 Area 3 Area 4 Questio
ID: 3124144 • Letter: Q
Question
Question 4
Graph the solution to the system:
Area 1
Area 2
Area 3
Area 4
Question 3
An in-home small business makes three types of holiday ornaments. Ornament A is a holiday mermaid that generates $6 profit and requires 2 minutes cutting, 3 minutes sewing and 2 minutes decorating. Ornament B is a holiday bunny that generates $5 profit and requires 1 minute cutting, 3 minutes sewing and 1 minute decorating. Ornament C is a holiday wreath that generates $4 profit and requires 1 minute cutting, 2 minutes sewing and 2 minutes decorating. Each day there are 180 minutes available for cutting, 300 minutes available for sewing and 240 minutes available for decorating. State the constraint on sewing if A, B, and C are used to represent each of the ornaments in that order.
P = 2A + B + C
P = 6A + 5B + 4C
P = 3A + 3B + 2C
P = 2A + 3B + 2C
A manufacturer of residential kitchen mixers makes two models, a smaller capacity (6 cup) and a larger capacity (8 cup) mixer. The smaller mixer takes 2 hours to assemble and 1 hour to finish. The larger capacity mixer requires 3 hours to assemble and 3 hours to finish. The maximum number of hours available in the assembly department per day is 240 hours and the maximum number of hours available in the finishing department per day is 150 hours. If profit on the smaller capacity mixer is $20 each and profit on the larger capacity mixer is $65 each, state the constraint on the finishing department, where x represents the smaller capacity mixer and yrepresents the larger capacity mixer.
x + 2y 240
3x + 3y 150
2x + 3y 240
x + 3y 150
Question 1
Given the following set of corner points for the feasible solution set,
(3, 0), (5, 0), (7, 1), (4, 6), (2, 3)
identify the maximum value for the objective function P = 2x + 4y.
P = 30
P = 32
P = 36
P = 48
a.Area 1
b.Area 2
c.Area 3
d.Area 4
2x+ y 3 x20, y 20Explanation / Answer
Question 1
Given the following set of corner points for the feasible solution set,
(3, 0), (5, 0), (7, 1), (4, 6), (2, 3)
identify the maximum value for the objective function P = 2x + 4y.
Put all the values one by one:
(3, 0), = 2x + 4y = 2*3 + 4*0 = 6
(5, 0), = 2x + 4y = 2*5 + 4*0 = 10
(7, 1), = 2x + 4y = 2*7 + 4*1 = 18
(4, 6), = 2x + 4y = 2*4 + 4*6 = 32
(2, 3) = 2x + 4y = 2*2 + 4*3 = 16
So, option B
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