Assume that the given procedure yields a binomial distribution with n trials and

Question

Assume that the given procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma. Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma2 and the maximum usual value mu plus 2 sigma+2.
In an analysis of preliminary test results from the a gender-selection method, 43 babies are born and it is assumed that 50% of babies are girls, so nequals=43 and pequals=0.5.
The value of the mean is = ............
(Simplify your answer.)
The value of the standard deviation is = ...........
(Round to one decimal place as needed.)
The minimum usual value is mu minus 2 =......
(Round to one decimal place as needed.)
The maximum usual value is mu plus +2 = ..........
(Round to one decimal place as needed.)

Explanation / Answer

a)

u = mean = np =    21.5 [ANSWER]

*************

b)
  
sigma = standard deviation = sqrt(np(1-p)) =    3.278719262 = 3.3 [ANSWER]

************

c)

Hence,

u - 2*sigma = 14.94256148 = 14.9 [ANSWER]

****************

d)

Hence,

u - 2*sigma = 28.05743852 = 28.1 [ANSWER]

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