Assume that the given procedure yields a binomial distribution with n trials and

Question

Assume that the given procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the given values of n and p to find the mean mu and standard deviation sigma . Also, use the range rule of thumb to find the minimum usual value mu minus 2 sigma 2 and the maximum usual value mu plus 2 sigma +2. In an analysis of preliminary test results from a gender-selection method, 38 38 babies are born and it is assumed that 50% of babies are girls, so n equals = 38 and p equals = 0.5.

Explanation / Answer

Slution : mean (µ): = n * p

standard deviation (): [ n*p*(1-p) ]^.5

Once you calculate the mean and standard deviation, you can calculate the minimum usual value and the max usual value.

Now, in our problem:

n = 38

p = .5

so,

the mean would be: 36*.5 =18

the standard deviation would be: [ (mean)(.5) ]^.5 = 3

Next, we find the minimum and maximum usual values according to the equations you gave:

minimum: mean - 2(standard deviation)

= 18 - 2( 3 )

= 12

maximum: mean + 2(standard deviation)

= 18 + 2( 3 )

= 24

Answer

TY!

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