Assume that IQ is normally distributed, with mean 100 and standard deviation 15.
ID: 3126755 • Letter: A
Question
Assume that IQ is normally distributed, with mean 100 and standard deviation 15.
(a) What is the probability that a randomly selected per- sons IQ is over 120?
(b) Find the values of Q1, Q2, and Q3 for IQ.
(c) Find the values of lower = Q1 1.5(Q3 Q1) and upper = Q3 + 1.5(Q3 Q1) for IQ. Recall that these were cutoffs for outliers.
(d) Find the probability of an outlier for IQ for a single person based on your values for (c).
(e) If we randomly selected 10 people, what is the prob- ability their average IQ is over 105?
Explanation / Answer
(a)For x=120,
Z=(x-)/=(120-100)/15=1.33
Thus, P(x>120)=P(z>1.33)=1-P(z<1.33)=1-0.9082=0.0918
(b) For the first quartile, say, q1, and the area to the left is .25.
From the standard normal table it has been found that z=-0.67
Thus, q1=-0.67*+=-0.67*15+100=89.95
Similarly, q3=+0.67*15+100=110.05
(c)Q1-1.5(Q3-Q1)=89.95-1.5(110.05-89.95)
=59.8
Q3+1.5(Q3-Q1)=110.5+1.5(110.05-89.95)
=140.2
(e)If 10 people are selected then the mean is 100 and standard deviation 15/sq rt10=4.74
For x=105, z=(105-100)/4.74=1.05
P(z>1.05)=0.1469
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