5) t-test for a mean 5 points Given the t-test information from excel and hypoth
ID: 3126880 • Letter: 5
Question
5) t-test for a mean 5 points
Given the t-test information from excel and hypotheses below; answer the following questions.
Hypotheses: H0: There is no significant difference between the mean ratings of laptops and tuition.
Ha: There is a significant difference between these two variables.
T-Test Assuming Equal Variances from Excel:
Laptops
Tuition
Mean
2.85
3.585858586
Variance
1.037878788
1.143063286
Observations
100
99
Pooled Variance
1.090204071
Hypothesized Mean Difference
0
df
197
t Stat
-4.970859875
P(T<=t) one-tail
7.22478E-07
t Critical one-tail
1.652625219
P(T<=t) two-tail
1.44496E-06
t Critical two-tail
1.972079034
A) What is the p-value?
B) Do you reject the null? Why or why not?
C) What is your conclusion?
D) Is the general hypothesis of: “If laptops then more enrollment,” supported by this t-test? Why or why not?
Laptops
Tuition
Mean
2.85
3.585858586
Variance
1.037878788
1.143063286
Observations
100
99
Pooled Variance
1.090204071
Hypothesized Mean Difference
0
df
197
t Stat
-4.970859875
P(T<=t) one-tail
7.22478E-07
t Critical one-tail
1.652625219
P(T<=t) two-tail
1.44496E-06
t Critical two-tail
1.972079034
Explanation / Answer
(A)
Alternative hypothesis suggest that test is two tailed. So p-value of the test will be 1.44496E-06 or 0.00000144496.
(B)
Since P-value is almost 0 so we reject the null hypothesis.
(C)
Conclusion:
There is a significant difference between these two variables.
(D)
In this case test is right tailed so one tail p-value 7.22478E-07 will be used, But is also very small so we reject the null hypothesis. That is t-test supports “If laptops then more enrollment,”.
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