The following data were collected from a repeated-measures study. X2 = 332 G = 6
ID: 3129663 • Letter: T
Question
The following data were collected from a repeated-measures study. X2 = 332 G = 60 Treatments Participant A B C D Participant (1) 6 3 3 0
Participant (2) 4 4 2 2 Participant( 3) 4 2 0 2 Participant( 4) 0 7 7 4 T = 24 T = 16 T = 12 T = 8 SS = 24 SS = 14 SS = 26 SS = 8 k=4 , n=4 , N=16 . a. State the null hypothesis. (1 POINT) b. Compute the necessary hypothesis test using a two-tailed test with = .05. Show your calculations. (5 POINTS) c. Make a decision about your null hypothesis. (Include the critical value you used to base your decision.) (1 POINT) d. Write an APA format statement summarizing your findings. (Include a measure of effect size if necessary.) (2 POINTS) e. Explain what would need to be done next to follow up on any significant effects. (2 POINTS)
Explanation / Answer
A)
Null hypothesis: All the treatments means are equal
Alternative hypothesis: Atleast one treatment mean is not same
alpha:5% level
Test statistic:
F =0.705
Conclusion: F cal= 0.705 and F critical value=3.86
F cal < F critical value at 5% level.we accept the null hypothesis.
For Blocks
Null hypothesis: All the blocks means are equal
Alternative hypothesis: Atleast one block mean is not same
alpha:5% level
Test statistic:
F =0.484
Conclusion: F cal= 0.484 and F critical value=3.86
F cal < F critical value at 5% level.we accept the null hypothesis.
Anova: Two-Factor Without Replication SUMMARY Count Sum Average Variance I 4 12 3 6 II 4 12 3 1.333333 III 4 8 2 2.666667 IV 4 18 4.5 11 A 4 14 3.5 6.333333 B 4 16 4 4.666667 C 4 12 3 8.666667 D 4 8 2 2.666667 ANOVA Source of Variation SS df MS F P-value F crit Rows 12.75 3 4.25 0.705069 0.572639 3.862548 Columns 8.75 3 2.916667 0.483871 0.701707 3.862548 Error 54.25 9 6.027778 Total 75.75 15Related Questions
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