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Question# 1 . A person’s gender and the choice of their pet was recorded when 55

ID: 3129796 • Letter: Q

Question

Question# 1. A person’s gender and the choice of their pet was recorded when 550 people were surveyed. Based on the table above, what is the probability a person owns a cat given they are a female?

a. 0.24

b. 0.44

c. 0.367

d. 0.653

Question # 2. You are going to play two games. The probability you win the first game is 0.60. If you win the first game, the probability you will win the second game is 0.75. If lose the first game, the probability you win the second game is 0.55. What is the probability you win exactly one game?

Question # 3. You bought a new set of four tires from a manufacturer that just announced a recall because 7% of those tires are defective. What is the probability that at least one of yours is defective?

Question # 4. The probability model above describes the number of thunderstorms that a certain town may experience during the month of August. What should the value be in the missing cell?

a. 0.1

b. 0.3

c. 0.2

d. -0.2

Question# 5. Sue Anne owns a medium-sized business. The probability model below describes the number of employees that may call in sick on any given day. Based on the table above, what is the mean number of employees calling in sick each day?

Dog Cat Other Pet No Pet Female 120) 132 18 30 Male 135 70 20 25

Explanation / Answer

Answer to question# 1)

We need to find probability that a perosn owns the cat given they are female

Formula of conditional Probability

P(owns cat | Female) = P(owns cat AND Female ) / P(Female)

.

P(owns cat AND Female) = number of people who own cat and are female / total number of female

P(owns cat AND Female) = 132 / 550

.

P(female) = total number of females / total number of people

P(Female) = (120 +132 +18 +30) / 550

P(female) = 300/550

.

P(owns cat | Female) = (132 /550) / (300 /550)

P(owns cat | Female) = 132 /300

P(owns cat | Female) = 0.44

Thus the correct answer choice is: b . 0.44

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