Find the appropriate rejection regions for the large-sample test statistic ; in
ID: 3130295 • Letter: F
Question
Find the appropriate rejection regions for the large-sample test statistic ; in these eases: A right-tailed test with alpha = 0.01 A two-tailed test at the 5% significance level Refer to Exercise 9.1. Suppose that the observed value of the test statistic was z = 2.16. For the rejection regions constructed in parts a and b of Exercise 9.1, draw the appropriate conclusion for the tests. If appropriate, give a measure of the reliability of your conclusion. Find the appropriate rejection regions for the large-sample test statistic z in these cases: A left-tailed test at the 1% significance level. A two-tailed test with alpha = 0.01. Suppose that the observed value of the test statistic was z = -2.41. For the rejection regions constructedExplanation / Answer
Given that test statistic z = 2.16
We can conclude the test by using critical value and P-value.
We can find P-value or critical value by using EXCEL.
syntax for critical value and P-value is,
=NORMSINV(probability)
where probability = 1 - alpha when test is right tailed.
=1 - NORMSDIST(z)
where z is test statistic value.
And if test is two tailed then EXCEL syntax is,
=NORMSINV(probability)
where probability = alpha / 2
=2*(1-NORMSDIST(z))
a) A right tailed test with alpha = 0.01
Hypothesis for the test is,
H0 : mu = mu0 Vs H1 : mu > mu0
critical value = 2.33
And P-value = 0.02
Here Z < critical value and P-value > alpha
Accept H0 at 1% level of significance.
Conclusion : Population mean is equal to mu0.
b) a two tailed test at 5% significance level.
Hypothesis for the test is,
H0 : mu = mu0 Vs H1 : mu mu0
critical value = -1.96
P-value = 0.03
Here Z > critical value and P-value < alpha
Reject H0 at 5% level of significance.
Conclusion : Population mean is differ than mu0.
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