9 Supplementary Exercise 5.51 A consumer advocate claims that 60 percent of cabl

Question

9 Supplementary Exercise 5.51 A consumer advocate claims that 60 percent of cable television subscribers are not satisfied with their cable service. In an attempt to justify this claim, a randomly selected sample of cable subscribers will be polled on this issue (a) Suppose that the advocate's claim is true, and suppose that a random sample of 8 cable subscribers is selected. Assuming independence, use an appropriate formula to compute the probability that 6 or more subscribers in the sample are not satisfied with their service. (Do not round intermediate calculations. Round final answer to p in 1 decimal place. Round other final answers to 4 decimal laces.) Binomial, n Probability = (b) Suppose that the advocate's claim is true, and suppose that a random sample of 20 cable subscribers is selected. Assuming independence, find: (Do not round intermediate calculations. Round final answer to p in 1 decimal place. Round other final answers to 4 decimal places.) Binomial, n 1. The probability that 10 or fewer subscribers in the sample are not satisfied with their service Probability 2. The probability that more than 14 subscribers in the sample are not satisfied with their service Probability 3. The probability that between 14 and 16 (inclusive) subscribers in the sample are not satisfied with their service 4. The probability that exactly 16 subscribers in the sample are not satisfied with their service

Explanation / Answer

(a) n =8 and p = 0.6,

P(X>=6) = 0.3154

(b) n =20 and p = 0.6

   1.      P(X<=10) = 0.2447

   2.      P(X>14) =0.1256

   3.      P(14 <= X <= 16) =0.2341

   4.      P(X<=16) =0.0350

(c) P(X<=10) = 0.2446 = 24.46%

No, if the claim is true, the probability that 10 or fewer are not satisifed is only 24.46%

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