Chri rk: 5-2 MyStatLab: Module Five Problem Set Ex Scores 0.83 of 5 pts ing Scor

Question

Chri rk: 5-2 MyStatLab: Module Five Problem Set Ex Scores 0.83 of 5 pts ing Score: 31.67%(20.58 of 65 pts) A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of Two sample T for Men vs Women women. She randomly selected 55 men and 75 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The folowing results were Men obtained N Mean 55 1125 75 StDev 11.1 SE Mean 15 1183 142 Women 98% CI for mu Men-mu women 1108,-0.52) T-Test mu Men-mu Women (vs) T--261 P-0.0050 DF-127 (b) Identily the P-value and state the researcher's conclusion if the level of significance was -OO1 What is the P-value? P-value 005 State the researchers conchusion. Which of the following is corect? OA Reject H, there ss than the mean step pulse of women Reject Ho there is not sufficient evidence to conclude that the mean step pulse of men was le is sufficient evidence to conclude that the mean step pulse of men was less than the mean step pulse of women Fail to reject Ho,there is not sufficient evidence to conclude that the me an step pudse of men was less than the mean step pulse of women idence to conclude that the mearn step pulse of men was less than the mean step conclude that the mean step pulse of men was less than the mean step pulse of women XD Fail to reject Ho, there is sufficient evidence to conclude that the mean (e) what is the 98% confidence interval for the mean difference in pulse ntes of men, ersus women? Use ascending order Round to two decimal places as needeod) Enter your answer in the edit fields, then cliek Check Ansver

Explanation / Answer

a.) H0: µ1-µ2 = 0

H1: µ1<µ2

We will try to reject null hypothesis and prove tha alternate hypothesis, i.e. mean step pulse of men is less than women.

b.) t = ((x1-x2) - (µ1-µ2)) / (12/n1 + 22/ n2 )

= ((112.5 - 118.3)-0) / (((11.1)2/55)+((14.2)2/75))

= -2.61

P(t=-2.61) = 0.005

c.) We will reject the null hypothesis because p-value is lower than the significance level. Hence, we can say that the mean step pulse of men is lower than women.

d.) (-11.08,-0.52)

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