True or False Questions The ith row of the matrix product AB can be computed by
ID: 3137144 • Letter: T
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True or False Questions The ith row of the matrix product AB can be computed by multiplying A with the ith row vector of the matrix B. 1) 2) IfAB+BA+Cis defined then A, B and Care square matrices of the same size. 3) For any matrix A, and any positive integer n, we can always compute A". 4) If A and B are nxn matrices then (A+B) A2+B*+2AB 5) (kA+B)-1=-A-1+8-1 6) (A-In) (As + A4 + A3 + Az + A + I 7) If AB is not invertible then either A is not invertible or B is not invertible 8) IfA and B are symmetric matrices of the same size then AB is also a symmetric n) = A6-In for any nxn matrix A. matrix 9) If A is an nxn matrix and B is a symmetric matrix of the same size then ATBA is also a symmetric matrix. 10) It is possible to find a matrix such that A1-A.Explanation / Answer
1. False
ith row vector of AB is obtained by multiplying matrix A with ith column of B.
2. True
If AB and BA both are defined and their addition is defined, both should have same order. that order must be equal to C.
3. True
We can always compute An
4. False
(A+B)2= A2+B2+AB+BA
5. False
(kA+B)-1is not equal to the above, since the formula for (a+b)-1 is quite complex and not the above equation
6. False
(A-In)(A5+A4+A3+A2+A-In) = A6+A5+A4+A3+A2-A-(A5+A4+A3+A2+A-In) =A6-2A+In
7. True
Det(AB) = DetA.DetB
Given Det(AB) = 0
Det(A)Det(B)=0
Either A or B has determinant 0 hence not invertible.
8. False
If A and B are symmetric, then AB is also symmetric only if AB commutate
9. True
(ATBA)T=(BA)T(AT)T
(ATBA)T=(ATBT)A
(ATBA)T=(ATB)A [since B is symmetric]
10. Yes, It is possible, check for
A = ( 0 -1
1 0)
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