Calculate the number of grams of NaCl needed to prepare 100 mL of a 280 mOsm/L N
ID: 314777 • Letter: C
Question
Explanation / Answer
A solution of 1 mol/L NaCl has an osmolarity of 2 Osmol/L.
Osmolarity of 0.140 mol/L NaCl is 0.280 Osmol/L or 280 mOsmol/L or
58 grams in 1 liter gives 1molar solution and 0.140 molar in 100 ml need 812 milligrams of NaCl.
Glucose has same osmolarity as molarity so 5 grams is requried as 180 grams required for 1liter solution for 1molar
Glucose with 3 grams in 1000 ml will give 16mM or 16 Osm/ L solution and 34 mM of NaCl is formed from 2 grams in 1liter of water and will be multiplied by two to get the 68 Osm/L solution and the mixture will have 84 mOsm/L.
A 1.2% solution (w/v) of NaCl is isotonic with 7.2% of glucose
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