If a person is given the choice of an integer from 0 to 9, is it more likely tha

Question

If a person is given the choice of an integer from 0 to 9, is it more likely that he or she will choose an integer near the middle of the sequence than one at either end?

(a) If the integers are equally likely to be chosen, find the probability distribution for x, the number chosen.

(b) What is the probability that a person will choose a 2, 3, or 4? (Enter an exact number as an integer, fraction, or decimal.)


(c) What is the probability that a person will not choose a 2, 3, or 4? (Enter an exact number as an integer, fraction, or decimal.)

Explanation / Answer

this is the probability distribution

b. each events are mutually likely

so

probability that person will choose 2 is 1/10, similarly person will choose 3 is 1/10 and person will choose 4 is 1/10

so the probability is 1/10+1/10+1/10 = 3/10

c. probability that person will not choose 2 ,3 or 4 is 1-(Probability that the person will choose 2 ,3 or 4) = 1-(3/10) = 7/10

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