As we read in problem #60 on p. 102, the color of a person\'s eyes is determined

Question

As we read in problem #60 on p. 102, the color of a person's eyes is determined by a single pair of genes. Let B represent the dominant brown-eyed gene and b represent the recessive blue-eyed gene. Then, BB and Bb will all result in brown eyes while bb will result in blue eyes. In a particular population, let p1 be the probability that a randomly selected person has BB, p2 be the probability of Bb, and p3 the probability of bb. If 10 individuals are randomly selected, what is the probability that 5 are BB, 3 are Bb and 2 are bb?

Explanation / Answer

P(BB) = 10C5/N = 252/N

P(Bb) = 10C3/N = 120/N

P(bb) = 10C2/N = 45/N

Where N is the population size

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