As we reported all the beginning of this chapter. on June 16.1989. during (he se

Question

As we reported all the beginning of this chapter. on June 16.1989. during (he second round of the 1989 US. Open, four golfers- Doug Weaver. Mark Wiebe. Jerry Pate, and Nick Price nude hole' in one on the sixth hole at Oak Hill in Pitlsford. New York. Now- that you have studied the material in this chapter, you can determine for yourself the likelihood of such an event. According to the experts, the odds against a professional golfer making a hole in are 3708 to I. in other words, the probability is 1/3709 that a professional golfer will make a hole in one. One hundred fifty - five golfers participated in the second round. Determine the probability that at least 4 of the 155 golfers would get a hole in one on the sixth hole. Discuss your result. What assumptions did you make in solving pail (a)? Do those assumptions seem reasonable to you? Explain your answer.

Explanation / Answer

a) p is very low, and n is high, do normal approximation to binomial.

E(X)=mu=np=155*1/3709=0.0418

SD=sqrt npq=0.2044

P(X>=4)=P[Z>(4-0.0418)/0.2044]=P(Z>=19.36)=0.00001

Assumptions:10% condition: 155 is less than 10% golfers who would get a hole in one on the sixth hole.

Success/failure condition:np and nq are not at least 10, therefore, assumptions do not seem reasonable.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.