A market analyst wants to know if the new website he designed is showing increas

Question

A market analyst wants to know if the new website he designed is showing increased page views per visit. A customer is randomly sent to one of two different websites, offering the same products, but with different designs. The accompanying table shows the data from five randomly chosen customers from each website. Assume that the data come from a distribution that is Normally distributed. Complete parts a through c below. Click the icon to view the data table of website page views per visit. Find a 95% confidence interval for the mean difference,mu_1 - mu_2, in page views from the two websites.

Explanation / Answer

Answer to the question)

group I :

x1 = 6.8

s1 = 2.77

group II:

x2 = 5.8

s2 = 3.35

.

n1 = n2 = 5

.

The formula of standard error = sqrt(s1^2/n1+s2^2/n2)

SE = sqrt((2.77^2/5) + (3.35^2/5))

SE = 1.9440

.

The formula of confidence interval is:

(x1-x2) - t* SE , (x1-x2) + t*SE

t value for 95% confidence level and df =(5+5-2) = 8 is 2.306

.

On plugging the values we get

(6.8-5.8) - 2.306 * 1.944 , (6.8-5.8) + 2.306 *1.944

-3.4829 , 5.4829

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