Write out the Null H(0) and alternate (H(1)) Hypotheses for a one-tailed test to

Question

Write out the Null H(0) and alternate (H(1)) Hypotheses for a one-tailed test to determine whether the average transportation charge is less than $430.

H(0) = Average Transportation Charge…

H(1) =

u 430

sample mean (x) 412 sample

std dev (s)    102.1763182

n                            10

test statistic t =         ?             (x - u)/(s/sqrt(n))

critical t value      -1.833112933

probability                  0.5      will recalculate

Conduct the appropriate type of one-sample test-statistic to determine whether the average transportation charge is less than $430. ______

Based on The test statistic and the critical value, we reject the null hypothesis

Yes / No ???

If the true population average is $430, what is the likelihood (probability) of observing a sample average of 412 based on a sample size of 10?

Explanation / Answer

Set Up Hypothesis
Null, H0: U>430
Alternate, H1: U<430
Test Statistic
Population Mean(U)=430
Sample X(Mean)=412
Standard Deviation(S.D)=102.1763182
Number (n)=10
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =412-430/(102.1763182/Sqrt(10))
to =-0.557
| to | =0.557
Critical Value
The Value of |t | with n-1 = 9 d.f is 1.833
We got |to| =0.557 & | t | =1.833
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
P-Value :Left Tail -Ha : ( P < -0.5571 ) = 0.29553
Hence Value of P0.05 < 0.29553,Here We Do not Reject Ho

[ANSWER]
2. Do not Reject Ho

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