Suppose that we are to conduct the following hypothesis test: H0:H1:=>900900 Sup

Question

Suppose that we are to conduct the following hypothesis test: H0:H1:=>900900 Suppose that you also know that =180, n=100, x¯=937.8, and take =0.1. Draw the sampling distribution, and use it to determine each of the following: A. The value of the standardized test statistic: Note: For the next part, your answer should use interval notation. An answer of the form (,a) is expressed (-infty, a), an answer of the form (b,) is expressed (b, infty), and an answer of the form (,a)(b,) is expressed (-infty, a)U(b, infty). B. The rejection region for the standardized test statistic: C. The p-value is D. Your decision for the hypothesis test: A. Reject H1. B. Do Not Reject H1. C. Reject H0. D. Do Not Reject H0.

Explanation / Answer

Set Up Hypothesis
Null Hypothesis H0: U<=900
Alternate Hypothesis H1: U>900
Test Statistic
Population Mean(U)=900
Given That X(Mean)=937.8
Standard Deviation(S.D)=180
Number (n)=100
we use Test Statistic (Z) = x-U/(s.d/Sqrt(n))
Zo=937.8-900/(180/Sqrt(100)
Zo =2.1
| Zo | =2.1
Critical Value
The Value of |Z | at LOS 0.1% is 1.28
We got |Zo| =2.1 & | Z | =1.28
Make Decision
Hence Value of | Zo | > | Z | and Here we Reject Ho
P-Value : Right Tail - Ha : ( P > 2.1 ) = 0.0179
Hence Value of P0.1 > 0.0179, Here we Reject Ho

A. Zo =2.1
B. Reject Ho when >1.28
C. P -val : 0.0179
D. Reject Ho

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