Chapter 5 Section 2 Please answer questions a through e Trevor is interested in
ID: 3153954 • Letter: C
Question
Chapter 5 Section 2
Please answer questions a through e
Trevor is interested in purchasing the local hardware/sporting goods store in the small town of Dove Creek, Montana. After examining accounting records for the past several years, he found that the store has been grossing over $850 per day about 65% of the business days it is open. Estimate the probability that the store will gross over $850 for the following. (Round your answers to three decimal places.) (a) at least 3 out of 5 business days (b) at least 6 out of 10 business days (c) fewer than 5 out of 10 business days (d) fewer than 6 out of the next 20 business days If the outcome described in part (d) actually occurred, might it shake your confidence in the statement p = 0.65? Might it make you suspect that p is less than 0.65? Explain. Yes. This is unlikely to happen if the true value of p is 0.65. Yes. This is likely to happen if the true value of p is 0.65. No. This is unlikely to happen if the true value of p is 0.65. No. This is likely to happen if the true value of p is 0.65. (e) more than 17 out of the next 20 business days If the outcome described in part (e) actually occurred, might you suspect that p is greater than 0.65? Explain. Yes. This is unlikely to happen if the true value of p is 0.65. Yes. This is likely to happen if the true value of p is 0.65. No. This is unlikely to happen if the true value of p is 0.65. No. This is likely to happen if the true value of p is 0.65.Explanation / Answer
a)
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 5
p = the probability of a success = 0.65
x = our critical value of successes = 3
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 2 ) = 0.235169375
Thus, the probability of at least 3 successes is
P(at least 3 ) = 0.764830625 [ANSWER]
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b)
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 10
p = the probability of a success = 0.65
x = our critical value of successes = 6
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 5 ) = 0.248504491
Thus, the probability of at least 6 successes is
P(at least 6 ) = 0.751495509 [ANSWER]
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c)
Note that P(fewer than x) = P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 10
p = the probability of a success = 0.65
x = our critical value of successes = 5
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 4 ) = 0.09493408
Which is also
P(fewer than 5 ) = 0.09493408 [ANSWER]
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d)
Note that P(fewer than x) = P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 20
p = the probability of a success = 0.65
x = our critical value of successes = 6
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 5 ) = 0.000310575
Which is also
P(fewer than 6 ) = 0.000310575 [ANSWER]
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Part d is a small probability, so
OPTION A. Yes, it is unlikely to happen is p = 0.65. [ANSWER]
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e)
Note that P(more than x) = 1 - P(at most x).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 20
p = the probability of a success = 0.65
x = our critical value of successes = 17
Then the cumulative probability of P(at most x) from a table/technology is
P(at most 17 ) = 0.987882293
Thus, the probability of at least 18 successes is
P(more than 17 ) = 0.012117707 [ANSWER]
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This is also a small probability, so
OPTION A: Yes, this is unlikely if p = 0.65. [ANSWER]
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