A research firm claims that the distribution of the days of the week that people
ID: 3154313 • Letter: A
Question
A research firm claims that the distribution of the days of the week that people are most likely to order food for delivery is different from the distribution shown in the pie chart. You randomly select 499 people and record which day of the week each is most likely to order food for delivery. The table to the right shows the results. At alpha = 0.05 , test the research firm's claim.
Day Frequency_f
Sunday 42
Monday 17
Tuesday 29
Wednesday 41
Thursday 44
Friday 167
Saturday 159
Calculate the test statistic. font size increased by 1 font size increased by 1 font size increased by 1 chi squared equals39.686 (Round to three decimal places as needed.)
Determine the P-value. Pequals 0.000 (Round to three decimal places as needed.)
Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.
Reject Upper H 0 . At the 5 % significance level, there is enough evidence to conclude that the distribution of the days people order food for delivery differs from the expected distribution.
Explanation / Answer
The test statistic is given here to be 39.686
Degree of freedom = 7-1 = 6
The corresponding P-value using chi-square table will be 0.000
Conclusion : Since the P-value is much less than the signifcance level we reject the null hypothesis. Thus there is enough evidence to conclude that the distribution of days people ordered food for delivery differs from the expected distribution.
Note:- If you want me to calculate the test statistic value , please provide a snapshot of the pie chart which is refered in the question.
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