8.31 Refer to the Journal of Adolescence study of adolescents\' disclosure of th
ID: 3155175 • Letter: 8
Question
8.31
Explanation / Answer
Set Up Hypothesis
Null, H0: U=3
Alternate, H1: U>3
Test Statistic
Population Mean(U)=3
Sample X(Mean)=3.26
Standard Deviation(S.D)=0.93
Number (n)=222
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =3.26-3/(0.93/Sqrt(222))
to =4.165
| to | =4.165
Critical Value
The Value of |t | with n-1 = 221 d.f is 2.343
We got |to| =4.165 & | t | =2.343
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value :Right Tail - Ha : ( P > 4.1655 ) = 0.00002
Hence Value of P0.01 > 0.00002,Here we Reject Ho
True mean disclosure score is greater than 3
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.