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A cell phone company offers two plans to its subscribers. At the time new subscr

ID: 3155508 • Letter: A

Question

A cell phone company offers two plans to its subscribers. At the time new subscribers sign up, they are asked to provide some demographic information. The mean yearly income for a sample of 50 subscribers to Plan A is $46,600 with a standard deviation of $7,300. For a sample of 30 subscribers to Plan B, the mean income is $58,100 with a standard deviation of $6,300.

At the 0.05 significance level, is it reasonable to conclude the mean income of those selecting Plan B is larger? Hint: For the calculations, assume the Plan A as the first sample.

The test statistic is _______. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)

Explanation / Answer

Formulating the null and alternative hypotheses,              
              
Ho:   u1 - u2   >=   0  
Ha:   u1 - u2   <   0  
At level of significance =    0.05          
As we can see, this is a    left   tailed test.      
Calculating the means of each group,              
              
X1 =    46600          
X2 =    58100          
              
Calculating the standard deviations of each group,              
              
s1 =    7300          
s2 =    6300          
              
Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):              
              
n1 = sample size of group 1 =    50          
n2 = sample size of group 2 =    30          
Thus, df = n1 + n2 - 2 =    78          
Also, sD =    1545.574327          
              
Thus, the t statistic will be              
              
t = [X1 - X2 - uD]/sD =    -7.440599782   [ANSWER, TEST STATISTIC]

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Other details:      
              
where uD = hypothesized difference =    0          
              
Now, the critical value for t is              
              
tcrit =    -   1.664624645      
              
              
Also, using p values,              
              
p =    5.65464E-11          
              
Comparing this to the significance level,    WE REJECT THE NULL HYPOTHESIS.          

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