The probability that a person in the United States has type B^ + Wood is 11% fou

Question

The probability that a person in the United States has type B^ + Wood is 11% four unrelated people in the United States are selected at random Complete parts (a) through (d) Find the probability that all four have type B^ + blood The probability that all four have type B^ + blood is (Round to six decimal places as needed) Find the probability that none of the four have type B^ + blood The probability that none of the four have type B^ + blood is (Round to throe decimal places as needed) Find the probability that at least one of the four has type B^ + Blood The probability that at least one of the four has type B^ + Blood is (Round to three decimal places as needed) Which of the events can be considered unusual Explain Select all that apply The event in part (b) is unusual because its probability is less than or equal to 0.05 None of these events are unusual The event in part (c) is unusual because its probability is less than or equal to 0 05

Explanation / Answer

a) P[all four have type B blood ] = 0.11 * 0.11 *0.11 * 0.11 = 0.000146

b) P[ none of the four have type B] = [1-0.11]^4 = 0.627

c) 1 - [1-0.11]^4 = 1 - 0.627 = 0.373

d) I think option c) is correct.

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