Consider the following LP problem developed at Zafar Malik\'s Carbondale, Illino
ID: 3157070 • Letter: C
Question
Consider the following LP problem developed at Zafar Malik's Carbondale, Illinois, optical scanning firm Maximize Z= 1x1+1x2 (C1) 360 (C) Subject to:2x,+1X,s60 1x,+ 2X, On the graph on right, constraints C, and C, have been plotted a) Lizing the poin drawing tool, plot all he comer points for the feasible area The optimum solution is: Xi= (round your response to two decimal places) X2= (round your response to two decimal places, Optimal solution value Z = round, our response to no decimal places, d your response to two decimal places)Explanation / Answer
Solve (C1) and (C2),
The intersection point = B = (20,20)
Corner points Z = x1 + x2
A= (0,30) Z = 0 + 30 = 30
B= (20,20) Z = 20 + 20 = 40
C= (30,0) Z = 30 + 0 = 30
The Maximum value of Z = 40, the corresponding point is Optimum point B = (20,20)
a) The optimum solution is
X1 = 20
X2 = 20
The Optiomum solution of Z = 40
b) If raised the profit $3 of X1
Corner points Z = 3x1 + x2
A= (0,30) Z = 3(0) + 30 = 30
B= (20,20) Z = 3(20) + 20 =80
C= (30,0) Z = 3(30) + 0 = 90
The optimum solution (Point C) is
X1 = 30
X2 = 0
The Optiomum solution of Z = 90
c)
If raised the profit $1.25 of X1
Corner points Z = 1.25x1 + x2
A= (0,30) Z = 1.25(0) + 30 = 30
B= (20,20) Z = 1.25(20) + 20 = 45
C= (30,0) Z = 1.25(30) + 0 = 45
The optimum solution (Point B and C) is
X1 = 30
X2 = 0
and X1 = 20, X2 = 20
The Optiomum solution of Z = 45
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.