1) Suppose a 95% confidence interval is computed for resulting in the interval (

Question

1) Suppose a 95% confidence interval is computed for resulting in the interval (112.4, 121.6). Then

there is a 95% chance that falls within the interval (112.4, 121.6).

95% of all the possible samples produce intervals that do capture

  95% of the time, falls within the interval (112.4, 121.6).

  95% of all the possible values of fall within the interval (112.4, 121.6).

2) What is the maximum sample size needed to estimate the proportion of adults in US who vote regularly and want to be 95% sure that the error of our estimate will not exceed 0.06, if we have no information about the true proportion? (Answer should be rounded up to nearest integer)

3)What is the maximum sample size needed to estimate the proportion of adults in US who vote regularly and want to be 95% sure that the error of our estimate will not exceed 0.06, if we use the 2012 Voter Turnout information about the true proportion is 0.59? (Answer should be rounded up to nearest integer)

4) The larger the sample size n, the smaller the maximum error of estimate.

True or False

5)The sample standard deviation S may be used in place of in the large-sample confidence interval for N provided n is at least _____.

there is a 95% chance that falls within the interval (112.4, 121.6).

95% of all the possible samples produce intervals that do capture

  95% of the time, falls within the interval (112.4, 121.6).

  95% of all the possible values of fall within the interval (112.4, 121.6).

Explanation / Answer

1.

OPTION A: there is a 95% chance that u falls within the interval (112.4, 121.6). [ANSWER]

***********************

2.

Note that      
      
n = z(alpha/2)^2 p (1 - p) / E^2      
      
where      
      
alpha/2 =    0.025  
As there is no previous estimate for p, we set p = 0.5.      
      
Using a table/technology,      
      
z(alpha/2) =    1.959963985  
      
Also,      
      
E =    0.06  
p =    0.5  
      
Thus,      
      
n =    266.7679737  
      
Rounding up,      
      
n =    267   [ANSWER]

*******************************************

Hi! Please submit the next part as a separate question. That way we can continue helping you! Please indicate which parts are not yet solved when you submit. Thanks!

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.