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United Oil Company is attempting to develop a reasonably priced unleaded gasolin

ID: 3157871 • Letter: U

Question

United Oil Company is attempting to develop a reasonably priced unleaded gasoline that will deliver higher gasoline mileages than can be achieved by its current unleaded gasolines. As part of its development process, United Oil wishes to study the effect of two independent variables—x1, amount of gasoline additive RST (0, 1, or 2 units), and x2, amount of gasoline additive XST (0, 1, 2, or 3 units), on gasoline mileage, y. Mileage tests are carried out using equipment that simulates driving under prescribed conditions. The combinations of x1 and x2 used in the experiment, along with the corresponding values of y, are given below.

  

  

Using the model, y = 0 + 1x1 + 2x12 + 3x2 + 4x22 + , calculate the point estimate.

(Moreover, consider the mean mileage obtained by all gallons of the gasoline when it is made with one unit of RST and two units of XST (a combination that the data on the page margin indicates would maximize mean mileage). Do not round intermediate calculations. Round your answer to 4 decimal places.)

   

RST
Units
(x1) XST
Units
(x2) Gas Mileage
(y, mpg) 0 0 27.19 0 0 28.24 0 0 28.78 1 0 29.62 1 0 30.27 2 0 28.40 2 0 29.69 0 1 32.52 0 1 33.31 1 1 33.36 1 1 34.33 0 2 32.21 0 2 33.94 1 2 34.84 1 2 35.98 1 2 35.17 2 2 33.34 2 2 34.03 2 2 34.27 1 3 33.70 2 3 33.29 2 3 33.35

Explanation / Answer

United Oil Company is attempting to develop a reasonably priced unleaded gasoline that will deliver higher gasoline mileages than can be achieved by its current unleaded gasolines. As part of its development process, United Oil wishes to study the effect of two independent variables—x1, amount of gasoline additive RST (0, 1, or 2 units), and x2, amount of gasoline additive XST (0, 1, 2, or 3 units), on gasoline mileage, y. Mileage tests are carried out using equipment that simulates driving under prescribed conditions. The combinations of x1 and x2 used in the experiment, along with the corresponding values of y, are given below.

Regression Analysis

0.941

Adjusted R²

0.927

n

22

R

0.970

k

4

Std. Error

0.689

Dep. Var.

y

ANOVA table

Source

SS

df

MS

F

p-value

Regression

129.4502

4  

32.3626

68.14

3.08E-10

Residual

8.0739

17  

0.4749

Total

137.5242

21  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=17)

p-value

95% lower

95% upper

Intercept

28.2730

0.3172

89.147

3.80E-24

27.6039

28.9421

x1

3.0537

0.6444

4.739

.0002

1.6940

4.4133

x1^2

-1.3570

0.3077

-4.410

.0004

-2.0062

-0.7077

x2

5.1891

0.4513

11.499

1.93E-09

4.2370

6.1412

x2^2

-1.2856

0.1649

-7.797

5.17E-07

-1.6334

-0.9377

Predicted values for: y

95% Confidence Interval

95% Prediction Interval

x1

x1^2

x2

x2^2

Predicted

lower

upper

lower

upper

Leverage

1

1

2

4

35.20568

34.63040

35.78097

33.64202

36.76935

0.157

The regression line is

mean mileage =28.2730+3.0537*RST-1.3570*RST2+ 5.1891*XST -1.2856*XST2

Moreover, consider the mean mileage obtained by all gallons of the gasoline when it is made with one unit of RST and two units of XST (a combination that the data on the page margin indicates would maximize mean mileage). Do not round intermediate calculations. Round your answer to 4 decimal places.)

  

when RST =1 and XST=2,

mean mileage =28.2730+3.0537*1-1.3570*12+ 5.1891*2 -1.2856*22

= 35.2057

Point estimate=35.2057

Regression Analysis

0.941

Adjusted R²

0.927

n

22

R

0.970

k

4

Std. Error

0.689

Dep. Var.

y

ANOVA table

Source

SS

df

MS

F

p-value

Regression

129.4502

4  

32.3626

68.14

3.08E-10

Residual

8.0739

17  

0.4749

Total

137.5242

21  

Regression output

confidence interval

variables

coefficients

std. error

   t (df=17)

p-value

95% lower

95% upper

Intercept

28.2730

0.3172

89.147

3.80E-24

27.6039

28.9421

x1

3.0537

0.6444

4.739

.0002

1.6940

4.4133

x1^2

-1.3570

0.3077

-4.410

.0004

-2.0062

-0.7077

x2

5.1891

0.4513

11.499

1.93E-09

4.2370

6.1412

x2^2

-1.2856

0.1649

-7.797

5.17E-07

-1.6334

-0.9377

Predicted values for: y

95% Confidence Interval

95% Prediction Interval

x1

x1^2

x2

x2^2

Predicted

lower

upper

lower

upper

Leverage

1

1

2

4

35.20568

34.63040

35.78097

33.64202

36.76935

0.157

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