Assume that a simple random sample has been selected from a normally distributed
ID: 3158131 • Letter: A
Question
Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses, test statistic. P-valuc. and stale the final conclusion that addresses the original claim. In a manual on how to have a number one song, it is stated that a song must be no longer than 210 seconds. A simple random sample of 40 currei hit songs results in a mean length of 241.5 sec and a standard deviation of 56.91 sec. Use a 0.05 significance level and the accompanying Minital display to test the claim that the sample is from a population of songs with a mean greater than 210 sec. What do these results suggest about the advice given in the manual? Click the icon to view the Minitab display. H_0; mu = 210 sec H_1; mu > 210 sec H_0; mu 210 sec H_0; mu > 210 sec H_1; mu lessthanorequalto 210 sec H_0; mu = 210 sec H_1; mu lessthanorequalto 210 sec Identify the test statistic. t = square box Identify the P-value The P-value is square box.Explanation / Answer
Part 1
Correct alternative for null and alternative hypothesis is A.
Answer = A
Part 2
Test statistic = t = 3.50 (rounded to two decimal places)
Part 3
P-value = 0.001 (rounded to three decimal places)
[The detail test for more reference is given as below:]
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
210
Level of Significance
0.05
Sample Size
40
Sample Mean
241.5
Sample Standard Deviation
56.91
Intermediate Calculations
Standard Error of the Mean
8.9983
Degrees of Freedom
39
t Test Statistic
3.5007
Upper-Tail Test
Upper Critical Value
1.6849
p-Value
0.0006
Reject the null hypothesis
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
210
Level of Significance
0.05
Sample Size
40
Sample Mean
241.5
Sample Standard Deviation
56.91
Intermediate Calculations
Standard Error of the Mean
8.9983
Degrees of Freedom
39
t Test Statistic
3.5007
Upper-Tail Test
Upper Critical Value
1.6849
p-Value
0.0006
Reject the null hypothesis
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