A simple random sample of 42 adults is obtained from a normally distributed popu

Question

A simple random sample of 42 adults is obtained from a normally distributed population, and each person's red blood cell count (in cell per microlitre) is measured. The sample mean is 5.28 and the sample standard deviation is 0.51. Use a 0.01 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 5.4, which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample group? What are the null and alternative hypotheses? H_0: mu

Explanation / Answer

Here we have to test the hypothesis that,

H0 : mu = 5.4 Vs H1 : mu < 5.4

Option b) is correct.

Here we use on sample t-test because population standard deviation is unknown.

Given values are,

n = 42

Xbar = 5.28

sd = 0.51

a = 0.01

mu = 5.4

This we can done using TI_83 calculator .

STeps :

STAT --> TESTS --> 2:T-Test --> ENTER --> Highlight on Stats --> ENTER --> Input all the values --> select alternative : <mu0 --> ENTER --> Calculate --> ENTER

Results are :

The test statistic t = -1.52488

P-value = 0.067 = 0.07

P-value > alpha (0.01)

Accept H0 at 1% level of significance.

Conclusion :There is sufficient evidence to say that the population mean is 5.4.

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