{Exercise 14.39} Almost all U.S. light-rail systems use electric cars that run o
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Question
{Exercise 14.39} Almost all U.S. light-rail systems use electric cars that run on tracks built at street level. The Federal Transit Administration claims light-rail is one of the safest modes of travel, with an accident rate of .99 accidents per million passenger miles as compared to 2.29 for buses. The following data show the miles of track and the weekday ridership in thousands of passengers for six light-rail systems (USA Today, January 7, 2003). Use these data to develop an estimated regression equation that could be used to predict the ridership given the miles of track.
Compute b0 and b1 (to 3 decimals if necessary). b1 1.7554 b0 -6.7629 Complete the estimated regression equation (to 3 decimals if necessary). = -6.7629 + 1.7554 x Compute the following (to 3 decimals if necessary). SSE : SST : SSR : MSE : What is the coefficient of determination (to 1 decimal)? Note: report r2 between 0 and 1. Suppose that Charlotte is considering construction of a light-rail system with 30 miles of track. Develop a 95% prediction interval for the weekday ridership for the Charlotte system (to 1 decimal if necessary). ( , )
Miles of Track 15 17 38 21 47 31 34 Ridership (1000s) 15 35 81 31 75 30 42 City Cleveland Denver Portland i tla.is| Sacramento San Diego San Jose St. LouisExplanation / Answer
The regression Analysis is given as below:
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.844471444
R Square
0.713132019
Adjusted R Square
0.655758423
Standard Error
14.41324376
Observations
7
ANOVA
df
SS
MS
F
Significance F
Regression
1
2582.149165
2582.149
12.42962
0.01681901
Residual
5
1038.707978
207.7416
Total
6
3620.857143
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
-6.762870781
15.43251993
-0.43822
0.679511
-46.43342618
32.90768462
Miles of track
1.755369928
0.497897244
3.525567
0.016819
0.475484318
3.035255539
The regression equation is given as below:
Readership = -6.7629 + 1.7554*Miles of track
Compute the following (to 3 decimals if necessary).
SSE: 1038.708
SST: 3620.857
SSR: 2582.149
MSE: 207.742
What is the coefficient of determination (to 1 decimal)?
The coefficient of determination or the value of R square is given as 0.713 which means about 71.3% of the variation in the dependent variable readership is explained by the independent variable miles of track.
Suppose that Charlotte is considering construction of a light-rail system with 30 miles of track. Develop a 95% prediction interval for the weekday ridership for the Charlotte system (to 1 decimal if necessary). ( , )
Confidence Interval Estimate
Data
X Value
30
Confidence Level
95%
Intermediate Calculations
Sample Size
7
Degrees of Freedom
5
t Value
2.570582
XBar, Sample Mean of X
29
Sum of Squared Differences from XBar
838
Standard Error of the Estimate
14.41324
h Statistic
0.14405
Predicted Y (YHat)
45.89823
For Average Y
Interval Half Width
14.0621
Confidence Interval Lower Limit
31.8361
Confidence Interval Upper Limit
59.96034
For Individual Response Y
Interval Half Width
39.6292
Prediction Interval Lower Limit
6.2690
Prediction Interval Upper Limit
85.52747
Confidence interval = (6.3, 85.5)
SUMMARY OUTPUT
Regression Statistics
Multiple R
0.844471444
R Square
0.713132019
Adjusted R Square
0.655758423
Standard Error
14.41324376
Observations
7
ANOVA
df
SS
MS
F
Significance F
Regression
1
2582.149165
2582.149
12.42962
0.01681901
Residual
5
1038.707978
207.7416
Total
6
3620.857143
Coefficients
Standard Error
t Stat
P-value
Lower 95%
Upper 95%
Intercept
-6.762870781
15.43251993
-0.43822
0.679511
-46.43342618
32.90768462
Miles of track
1.755369928
0.497897244
3.525567
0.016819
0.475484318
3.035255539
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