Find the critical value z.a/2 that corresponds to a 98% confidence level. Use th

Question

Find the critical value z.a/2 that corresponds to a 98% confidence level. Use the given data to find the minimum sample size required to estimate the population proportion. Margin of error: 0.001; confidence level: 92%; p and q unknown Assume that a sample is used to estimate a population proportion p. find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. Find the mean of the given probability distribution. The random variable x Is the number of houses sold by a realtor in a single month at the serfdom's Real Estate office. Its probability distribution is as follows.

Explanation / Answer

Q15.
Critical Value
The Value of |Z | at LOS 0.02% is 2.33

Q17.
Margin of Error = Z a/2 Sqrt(p*(1-p)/n))
x = Mean
n = Sample Size
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=284
Sample Size(n)=1420
Sample proportion =0.2
Margin of Error = Z a/2 * ( Sqrt ( (0.2*0.8) /1420) )
= 1.645* Sqrt(0)
=0.017

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.