A ball rolls off a table with a horizontal velocity of 16 m/s. If it takes 1.5 s

Question

A ball rolls off a table with a horizontal velocity of 16 m/s. If it takes 1.5 s for it to reach the floor: What is the vertical component of the ball's velocity just before it hits the floor? What is the horizontal component of the ball's velocity just before it hits the floor? A ball rolls off a platform that is 25 meters above the ground. The ball's horizontal velocity as it leaves the platform is 10 m/s. How much time does it take for the ball to hit the ground? How far from the base of the platform does the ball hit the ground?

Explanation / Answer

Solving first question

There is no accleration horizontally so horizontal velocity will be same

Horizontal component of ball after it reaches bottom=16 m/s

Vertical component=g*t=9.8*1.5=14.7 m/s

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