Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

1.1 all the parts please Substance a (J m nmole 7) b (m mole T He 3.44 x 10 0.02

ID: 3161564 • Letter: 1

Question

   1.1 all the parts please

Substance a (J m nmole 7) b (m mole T He 3.44 x 10 0.0224 x10 24.8 x 10 0.0266 x 10 366 x 10 0.0429 x10 CO H20 580 x 10 0.0319 10 Constants a and b in van der 8 equation for Pressure in Pa, specific volume v in m T in kelvins, and R 8.314 x 103 J/(kmole K). Section 1.1 (and Physics 51) xi.1 A section of railroad track has a length of 12 meters and a linear density (A) of 50 kg/m. The volume mass density (p) of steel is 8000 kg/m (a) Determine the change in length when the temperature increases by 10 degrees centigrade (b) Determine the change in volume (c) Determine the value of the volume coefficient of thermal expansion for steel. Railroad tracks have a complicated shape, so you can model it the cross- section as square or as circular (whichever you prefer). You may assume the linear coefficient of thermal expansion is 1.1 X 10 5 K xi.2 The by a volume of gas is a linear function of the temperature Imagine a container filled with an ideal gas. It is fitted with a

Explanation / Answer

part a )

L' = L*(1+alpha*dT)

alpha = linear coefficient = 1.1 xx 10^-5 K^-1

dT = 10

L = 12m

dL = L*alpha*dT

dL = 12 * 1.1*10^-5 * 10

dL = 1.32 x 10^-3 m

part b )

volumetric expansion coefficient = 3 * linear expansion coefficient

gamma = 3*alpha

gamma = 3.3 x 10^-5

mass = length * linear mass density = 600 kg

volume = mass/density

volume = 600/8000 = 0.075 m^3

dV = V*gamma*dT

dV = 2.475 x 10^-5 m^3

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote