Capacitors Consider the system of capacitors shown in the figure below (C_1 = 5.

Question

Capacitors

Consider the system of capacitors shown in the figure below (C_1 = 5.00 mu F, C_2 = 7.00 mu F). (a) Find the equivalent capacitance of the system. 4.2 mu F (b) Find the charge on each capacitor. mu C (on C_1) mu C (on C_2) mu C (on the 6.00 mu F capacitor) mu C (on the 2.00 mu F capacitor) (c) Find the potential difference across each capacitor. V (across C_1) V (across C_2) V (across the 6.00 mu F capacitor) V (across the 2.00 mu F capacitor) (d) Find the total energy stored by the group. mJ

Explanation / Answer

a] Ceq = 5*6/[5+6] + 2*7/[2+7]

= 4.283 uF

b] Charge on C1 = CV =90*5*6/[5+6] = 245 uC

Charge on C2 = CV =90*2*7/[2+7] = 140 uC

charge on 6uF =245 uC

charge on   2uF = 140 uC

c] voltage on C1 = Q/C = 245.5/5 = 49.1 V

voltage on C2 = Q/C =140/7 = 20 V

voltage on 6uF = 245/6 = 40.9 V

voltage on   2uF = 90-20 =70V

d] E = 0.5 CV^2

= 0.5*4.283e-6*90^2

= 0.01734 J

= 17.34 mJ

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