Each plate of an ideal air-filled parallel-plate capacitor has an area of 0.0020

Question

Each plate of an ideal air-filled parallel-plate capacitor has an area of 0.0020 m2, and the separation of the plates is 0.09 mm. An electric field of 2.1x106 N/C is present between the plates. What is the charge on the capacitor?

nC

An ideal parallel-plate capacitor consists of two parallel plates of area A separated by a distance d. This capacitor is connected across a battery that maintains a constant potential difference between the plates. If the separation between the plates is now doubled, the magnitude of the charge on the plates will

A. fourth

B. half

C. quadruple

D. third

E. double

Explanation / Answer

V = E d

= 0.09 * 10-3 * 2.1 * 106 = 189 volts

C = e0 A / d = 8.85 * 10-12 * 0.002 / 0.09 * 10-3

= 1.97 * 10-10 F

Charge Q = C V = 1.97 * 10-10 F * 189

Q = 3.72 * 10-8 C = 37.2 nC

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