distance is between the earth and the sun, moon, Jupiter (closest), Jupiter (far
ID: 3163317 • Letter: D
Question
distance is between the earth and the sun, moon, Jupiter (closest), Jupiter (farthest) center of galaxy, and andromeda
Explanation / Answer
Let the mass of the body = 70 kg, By applying the Newton's Universal law of gravitation
[a]
The Sun
Fyou-sun = G m* Msun/ r2= 6.67*10-11*70*2*1030/ (149.6*109)2 [ r is the distance is between the earth and the sun]
F you-sun = 0.42N
[b]
The Moon
Fyou-moon = G m* Mmoon/ r2= 6.67*10-11*70*7.35*1022/ (3.844*108)2 [ r is the distance is between the earth and the moon]
Fyou-moon = 0.0023N
[c]
The planet Jupiter [ as it is closest to Earth]
Fyou-jupiter = G m* Mjupiter / r2
Here; r = [distance of Jupiter- Sun] - [distance of Sun- Earth]
r = 778.5*109 - 149.6*109 =628.9 *109 m
Fyou-jupiter = G m* Mjupiter / r2= 6.67*10-11*70*1.9*1027/ (628.9*109)2 = 2.24*10-5 N
Fyou-jupiter = 2.24*10-5 N [ as it is closest to Earth]
[d]
The planet Jupiter [ as it is farthest from Earth]
Fyou-jupiter = G m* Mjupiter / r2
Here; r = [distance of Jupiter- Sun] + [distance of Sun- Earth]
r = 778.5*109+ 149.6*109 =928.1 *109 m
Fyou-jupiter = G m* Mjupiter / r2= 6.67*10-11*70*1.9*1027/ (928.1*109)2 = 1.03*10-5 N
Fyou-jupiter =1 .03*10-5 N [ as it is farthest from Earth]
[e]
Centre of gravity
FCentre of gravity = G m* Mblack hole / r2
Mblack hole = 3 *106 * M sun=3 *106 * 2*1030 kg= 6*1036 kg
r= 28,000 light years= 28*103* 9.5*1015 m = 266*1018 m [ 1 light year= 9.5*1015 m]
FCentre of gravity = G m* Mblack hole / r2 = 6.67*10-11*70*6*1036 / ( 266*1018 )2 = 3.96*10-13 N
FCentre of gravity = 3.96*10-13 N
[f]
Andromeda
FAndromeda = G m* MAndromeda/ r2
MAndromeda = 100 *109 * M sun= 1011 * 2*1030 kg= 2*1041 kg
r= 2.5 million light years= 2.5*106* 9.5*1015 m = 23.75*1021m [ 1 light year= 9.5*1015 m]
FAndromeda = G m* MAndromeda/ r2 = 6.67*10-11*70*2*1041 / ( 23.75*1021 )2 = 1.66*10-12 N
FAndromeda= 1.66*10-12 N
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