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O webassignnetwebsstudent/Assignment-Responses/submit?dep 15623598 to the favorites bar by selecting or by importing your favorites. o on points I Previous Nowers Sercp105 Tarzan swings on a 29.0-m-long vine initially indined at an angle of 30.oe with the vertical. (a) what is his speed at the bottom of the swing if he starts from rest? 3.8 Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s? 8.6 Your response is within 10% of the correct value, This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate re four-digit accuracy to minimize roundoff error. m/s Need Help? Submit Answer Save Progress Practice Another Version 01 points I Previous Answers SerCP105 P 048 In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 2.0 m/s up a 23.0. inclined track. The combined mass of monkey and ded coefficient of kinetic friction between sled and indine is How far up the indine do the monkey and sled move? 12.8 from beginning and check each step carefully- m Your response differs significantly from the correct answer. Rework your solution th m Need Help? LReadIExplanation / Answer
You set up this problem by doing a drawing. Think about the vine hanging verically downwards.The end of the vine is 29m below the attachment point. Now the vine is moved sideways so that it makes an angle of 30° with the vertical. The end of the vine has now been lifted so that it is no longer 29m below the attachment point. From your drawing you should be able to see that the end of the vine is now
h = 29cos30° = 4.49m below the attachment point. If Tarzan clutches the vine it the end, he is 29-4.49m = 24.51 m above the base level. He has potential energy which is equal to PE = m*g*h
When he swings down, as the vine passes the lowest base level, the kinetic energy is equal to Tarzan's potential energy at the top of the swing. KE = 0.5*m*v²
Therefore: m*g*h = 0.5*m*v²
g*h = 0.5V²
9.81 * 24.51 = 0.5v²
V² = 240.44/0.5
V² = 480.88
v = 21.9m/s
For the second part of the problem if Tarzan has an itial speed of 3m/s, then he has the previous calculated potential energy, plus extra kinetic energy from his speed.
His total energy at the top is Pe = m*g*h + KE = 0.5*m*3²
This is all converted to KE at the bottom which is equal to the total energy at the top
m*g*h + 0.5*m*9 = 0.5*m*v²
Divide by m
9.81*24.51 + 0.5*9 = 0.5V²
489.88 = v²
V² = 489.88
v = 31.3 m/s which is speed at lowest point
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