Take a line as the rotating axis which is perpendicular to the force table and t

Question

Take a line as the rotating axis which is perpendicular to the force table and through its center. Draw on the figure the arms l_1, l_2, l_3 for F^vector_1, F^vector_2, F^vector_3 respectively. Use right hand rule to determine the directions of the torques about the rotating axis acted on the force table by F^vector_1, F^vector_2, F^vector_3 respectively. Write down the expression of the total torque acted on the force table in terms of l_1, l_2, l_3 and F_1, F_2, F_3 with correct signs which correspond to the directions of the three individual torques.

Explanation / Answer

When finding a torque is identify the axis. The axis is the point on which the object gonna rotate. The object whatever it is rotate around the center, so center here of the object would be the axis.

If the axis was in very center and if a force gonna exert a torque, it has to be applied at some point beside the axis.

In other word if you try to push and open a revolving object at the very center, nothing gonna happen because its not gonna rotate. But further out you apply the force, the more torque will you get for the amount of force you are exerting , so force here apply much more torque than a force applied.

Now here, I know the torque is

torque is F times D, or F times R , here you can call it R.

R represent the vector that points from the axis to the point where the force has applied.

Remember R is not entire radius necessarily and not a entire length of object. Technically this R is vector or position vector but regardless from the point of the axis to the point where force is applied.

The direction is not toward the axis , the direction is always away from the axis to the point. Where the force happens to be applied on the object.

Here the force is no representig total force necessarily it meant to be force which is perpendicular to the R, so this perpendicular component of the force exert on the object. The components parallel to the R does not exert force on object.

Force table:

Set up a force table , make sure the table is level up for the experiment. Mount a pulley on 200 mark and suspend a 100 gm over it. Mount a secon Pulley on 1200 mark and supend the weight of 200 gm over it.

Check the result for above procedure for setting equilibriant on the force table. This will be force is equal yo magnitude in given resultant but pulling in the opposite direction. Remove the center pin to see the ring remains at the equilibrium. Make sure that all strings are pointing exactly to the center of the pin, otherwise the angle will not be correct.

Torque = r * f

L = r * p

Where, L is linear momentum

P = angular momentum

F= F1 + F2+ F3

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