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For each problem: 1. define the alleles and describe the dominance hierarchy - \

ID: 3166443 • Letter: F

Question

For each problem: 1. define the alleles and describe the dominance hierarchy - "define the alleles" means that you need to tell me what allele each letter that you're using represents. - the "dominance hierarchy" tells me which allele is dominant, recessive, codominant, incompletely dominant, etc. - you should also tell me in this section if the gene is not autosomal i.e. if it is sex-linked 2. write out the cross phenotypically 3. write out the cross genotypically 4. draw the Punnett square Don't repeat the same gamete from the same individual 5. the question will ask you to do one or more of the following: a. calculate the phenotypic ratio of the offspring This ratio should be in the least common denominators if you didn't repeat the same gamete from the same individual when doing the Punnett square b. calculate the genotypic ratio of the offspring This ratio should be in the least common denominators if you didn't repeat the same gamete from the same individual when doing the Punnett square c. determine some probability Questions are on the back

Explanation / Answer

1. Red flower RR X White flower rr

F1               Rr Pink color

Red flower RR X Pink color Rr

F2             RR Red flower : Rr Pink flower
Genotypic ratio        1       :       1
Phenotypic ratio       1       :       1

2.   Father XaY X Mother XAXA

F1         XAXa She not hemophilic X XAY

F2          XAXA   XAXa XAY XaY

Probability = 1/4. XaY Hemophilic son

3.    Man hemophilia XaY   X Female XAXA

Probability = 0

4.   red-green color blindness is a sex linked recessive trait
Normal vision XCY X Colorblind XcXc

         XCXc-Normal vision : XcY - Colorblind Male

Probability = 0

5. Autosomal recessive aa - Sickle cell
Red-green color blindness is a sex linked recessive trait

Sickle cell and hemophilia aaXcY X AaXCXC Normal sickle cell and no hemophilia
                     Gametes Xca / aY X XCA / XCa

F1   XCXcAa   XCXcaa     XCYAa   XCYaa

Probability 2/4 = 1/2