Find the value of z for which the area of the shaded region under the standard n

Question

Find the value of z for which the area of the shaded region under the standard normal curve is 0.1587. The table gives the values of A(z), which are left tail areas. Determine mu and sigma by inspection. mu = sigma = The number of chocolate chips in an 18-ounce bag of chocolate chip cookies is normally distributed with mu = 1259 and sigma = 126 chips, What is the probability that a randomly selected bag contains between 1007 and 1511 chocolate chips? The probability that a randomly selected bag contains between 1007 and 1511 chocolate chips is.

Explanation / Answer

Area of shaded region = 0.1587

Left tailed area to z = 1- 0.1587

= 0.8413

Therefore z= 1

2) mu = 10 and

sigma =1

3) P(1007<X<1511) = P((1007-1259) / 126 <Z< (1511-1259)/126)

= P( -2<Z<2)

= 0.9772-0.0228

= 0.9544

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