Can I get help with this problem? The following data come from a study investiga

Question

Can I get help with this problem? The following data come from a study investigating a new method of measuring body composition, and give the body fat percentage (% fat), age and sex for 18 normal adults aged between 23 and 61 years (American Journal of Clinical Nutrition, 40, 834-839). A) calculate the sum of squares for error (SSE); B) calculate the standard error of estimate; C) calculate the regression line; D) interpret the regression coefficient (what is this telling us?)

Age %Fat Sex 23 9.5 M 27 7.8 M 39 31.4 F 45 27.4 M 50 31.1 F 53 42.0 F 56 32.5 F 58 33.0 F 60 41.1 F 23 27.9 F 27 17.8 M 41 25.9 F 49 25.2 F 53 34.7 F 54 29.1 F 57 30.3 F 58 33.8 F 61 34.5 F

Explanation / Answer

a)

b) SE of estimate is 529.66264/16=33.103915

c)

Regression Analysis: %Fat Y versus Age X

The regression equation is
%Fat Y = 3.22 + 0.548 Age X

d)

3.221 is the intercept of the fitted line or mean value of % fat for age = 0. However, we do not predict % fat for ages that are beyond the range of the age included in the sample.

0 548 is the slope of the fitted line This means for one 0.548 is the slope of the fitted line. This means for one year increase in age, percent of body fat increases by 0.548 on average.

Age X %Fat Y Trend values (Y-Fat Y)^2 23 9.5 15.8247 40.00183 27 7.8 18.0166 104.37892 39 31.4 24.5925 46.342056 45 27.4 27.8805 0.2308803 50 31.1 30.6204 0.2300162 53 42 32.2644 94.781907 56 32.5 33.9084 1.9835906 58 33 35.0043 4.0172185 60 41.1 36.1003 24.997 23 27.9 15.8247 145.81287 27 17.8 18.0166 0.0469156 41 25.9 25.6885 0.0447322 49 25.2 30.0724 23.740282 53 34.7 32.2644 5.9321474 54 29.1 32.8124 13.781914 57 30.3 34.4563 17.27483 58 33.8 35.0043 1.4503385 61 34.5 36.6483 4.6151929 SSE = 529.66264

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