Give your answer to 2 decimal places. Fill in the blank: The probability that a

Question

Give your answer to 2 decimal places.
Fill in the blank:
The probability that a child of these parents has blood type O is: _______ .

Give your answer to 4 decimal places.
Fill in the blank:
The probability that all three have blood type O is: _______ .

Give your answer to 3 decimal places.
Fill in the blank:
The probability that the first child has blood type O and the next two do not is: _______ .

Step 1:
Mendelian inheritance. Some traits of plants and animals depend on inheritance of a single gene. This is called Mendelian inheritance, after Gregor Mendel (1822–1884). This exercise is based on the following information about Mendelian inheritance of blood type. Each of us has an ABO blood type, which describes whether two characteristics called A and B are present. Every human being has two blood type alleles (gene forms), one inherited from our mother and one from our father.
Each of these alleles can be A, B, or O. Which two we inherit determines our blood type. The following table shows what our blood type is for each combination of two alleles:



We inherit each of a parent's two alleles with probability 0.5.
We inherit independently from our mother and father.

Jasmine has alleles A and O. Joshua has alleles B and O.

What is the probability that a child of these parents has blood type O?

Give your answer to 2 decimal places.
Fill in the blank:
The probability that a child of these parents has blood type O is: _______ .

Step 2:
Mendelian inheritance. Some traits of plants and animals depend on inheritance of a single gene. This is called Mendelian inheritance, after Gregor Mendel (1822–1884). This exercise is based on the following information about Mendelian inheritance of blood type. Each of us has an ABO blood type, which describes whether two characteristics called A and B are present. Every human being has two blood type alleles (gene forms), one inherited from our mother and one from our father.
Each of these alleles can be A, B, or O. Which two we inherit determines our blood type. The following table shows what our blood type is for each combination of two alleles:



We inherit each of a parent's two alleles with probability 0.5.
We inherit independently from our mother and father.

Jasmine has alleles A and O. Joshua has alleles B and O.

If Jasmine and Joshua have three children, what is the probability that all three have blood type O?

Give your answer to 4 decimal places.
Fill in the blank:
The probability that all three have blood type O is: _______ .

Step 3:
Mendelian inheritance. Some traits of plants and animals depend on inheritance of a single gene. This is called Mendelian inheritance, after Gregor Mendel (1822–1884). This exercise is based on the following information about Mendelian inheritance of blood type. Each of us has an ABO blood type, which describes whether two characteristics called A and B are present. Every human being has two blood type alleles (gene forms), one inherited from our mother and one from our father.
Each of these alleles can be A, B, or O. Which two we inherit determines our blood type. The following table shows what our blood type is for each combination of two alleles:



We inherit each of a parent's two alleles with probability 0.5.
We inherit independently from our mother and father.

Jasmine has alleles A and O. Joshua has alleles B and O.

What is the probability that the first child has blood type O and the next two do not?

Give your answer to 3 decimal places.
Fill in the blank:
The probability that the first child has blood type O and the next two do not is: _______ .

Alleles inherited Blood type A and A A and B AB A and O B and B B and O O and O

Explanation / Answer

Solution:-

Step1:

One half of the parents alleles are O, one quarter are A, and the other quarter are B.

Therefore, P(O)=0.5, P(A)=0.25, and P(B)=0.25.

P(Blood Type=O) = P(genotype=OO) = P(O)² = 0.5² = 0.25

The probability that a child of these parents has blood type O is 0.25

Step2:

Using the multiplication rule for independent events,

P(OO) = P(OO)³ = 0.25³ = 1/64 = 0.015625

The probability that all three have blood type O is:0.015625

Step3:

Probability of not getting blood type 0 is,

P(not OO) = 1 P(OO) = 1 0.25 = 0.75

P(OO and not OO) = P(OO)P(not OO)² = 0.25 0.75² = 0.141

The probability that the first child has blood type O and the next two do not is: 0.141

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