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To test the relationship between gender and ratings of a promiscuous partner, a

ID: 3178056 • Letter: T

Question

To test the relationship between gender and ratings of a promiscuous partner, a group of men and women was given a vignette describing a person of the opposite sex who was in a dating relationship with one, two, or three partners. Participants rated how positively they felt about the individual described in the vignette, with higher ratings indicating more positive feelings.

(a) Complete the F-table and make a decision to retain or reject the null hypothesis for each hypothesis test. (Assume experimentwise alpha equal to 0.05.)


State the decision for the main effect of gender.

Retain the null hypothesis. Reject the null hypothesis.    


State the decision for the main effect of promiscuity.

Retain the null hypothesis. Reject the null hypothesis.    


State the decision for the interaction effect.

Retain the null hypothesis. Reject the null hypothesis.    


(b) Based on the results you obtained, what is the next step?

Compute pairwise comparisons for the gender factor. Compute pairwise comparisons for the promiscuity factor.      Compute simple main effect tests for the significant interaction. No further analysis is needed, because none of the effects are significant.

Source of Variation SS df MS F Gender 5 Promiscuity Gender × Promiscuity 156 Error 570 114 Total 811

Explanation / Answer

Result:

Source of

SS

df

MS

F

Variation

Gender

5

1

5

1

Promiscuity

80

2

40

8

Gender ×Promiscuity

156

2

78

15.6

Error

570

114

5

Total

811

119


State the decision for the main effect of gender.

Table value of F(1,114) =3.92

Calculated F=1 which is < 3.92 the table value.

Retain the null hypothesis..    


State the decision for the main effect of promiscuity.

Table value of F(2,114) =3.076

Calculated F=8 which is > 3.076 the table value.

Reject the null hypothesis.    


State the decision for the interaction effect.

Table value of F(2,114) =3.076

Calculated F=15.6 which is > 3.076 the table value.

Reject the null hypothesis.    


(b) Based on the results you obtained, what is the next step?

Compute pairwise comparisons for the promiscuity factor.     

Source of

SS

df

MS

F

Variation

Gender

5

1

5

1

Promiscuity

80

2

40

8

Gender ×Promiscuity

156

2

78

15.6

Error

570

114

5

Total

811

119

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