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The average number of field mice per acre in a 5-acre wheat field is estimated t

ID: 3180341 • Letter: T

Question

The average number of field mice per acre in a 5-acre wheat field is estimated to be 12. Find the probability that fewer than 7 field mice are found: a. On a given acre b. On 2 of the next 3 acres inspected The arrival time at a certain coffee shop follows a Poison process with an arriving rate of 5 persons per minute. What is the probability of 7 people arming in 10 minutes? Suppose you have a bag with 4 yellow balls, 2 green balls, 3 red halls and 3 white balls. If I take out 7 balls (with replacement), what is the probability of taking out 2 yellow balls, 2 red balls and 3 white balls? Problem 3.73 from textbook. Impurities in a batch of final product of a chemical process often reflect a serious problem. From considerable plant data gathered, it is known that the proportion Y of impurities in a batch has a density function given by: f(y) = {10(1 - y)^9,0 lessthanorequalto y lessthanorequalto 1 0, elsewhere a. Verify that the above is a valid density function. b. A batch is considered not sellable and then not acceptable if the percentage of impurities exceeds 60%. With the current quality of the process, what is the percentage of batches that are not acceptable? The weight of a running shoe is normally distributed with a mean of 9.6 ounces and a standard deviation of 0.5 ounce. What is the probability that a shoe weighs more than 11 ounces? The University's trolley passes by a specific bus stop every 15 minutes. It is assumed that the waiting time for a student follows a continuous uniform distribution. a. What is the probability that a student must wait at least 10 minutes at the bus stop? b. What is the probability that a student must wait between 8 and 13 minutes at the bus stop? Compute the following: a. X ~ Continuous Uniform with A = 8 and B = 14. Find the probability that X is greater than 10.2 but less than 13.4. b. Y ~ Normal with mu = 250 and sigma^2 = 20^2. Find the probability that Y is greater than 236.6. c. What is the probability that X is less than 10.5 or Y is less than 260.7?

Explanation / Answer

Q5.

Mean ( u ) =9.6
Standard Deviation ( sd )=0.5
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P(X > 11) = (11-9.6)/0.5
= 1.4/0.5 = 2.8
= P ( Z >2.8) From Standard Normal Table
= 0.0026                  

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