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Test the claim about the population mean, mu, at the given level of significance

ID: 3180721 • Letter: T

Question


Test the claim about the population mean, mu, at the given level of significance using the given sample statistics. Claim: mu = 40; alpha = 0.04; sigma = 3.51. Sample statistics: x = 38.7, n = 60 A. The critical values are plusminus B. The critical value is Determine the outcome and conclusion of the test. Choose the correct answer below. A. Fail to reject H_0. At the 4% significance level, there is not enough evidence to support the claim. B. Reject H_0. At the 4% significance level, there is enough evidence to support the claim. C. Fail to reject H_0. At the 4% significance level there is not enough evidence to reject the claim. D. Reject H_0. At the 4% significance level, there is enough evidence to reject the claim.

Explanation / Answer

Given that,
population mean(u)=40
standard deviation, =3.51
sample mean, x =38.7
number (n)=60
null, Ho: =40
alternate, H1: !=40
level of significance, = 0.04
from standard normal table, two tailed z /2 =2.054
since our test is two-tailed
reject Ho, if zo < -2.054 OR if zo > 2.054
we use test statistic (z) = x-u/(s.d/sqrt(n))
zo = 38.7-40/(3.51/sqrt(60)
zo = -2.86888
| zo | = 2.86888
critical value
the value of |z | at los 4% is 2.054
we got |zo| =2.86888 & | z | = 2.054
make decision
hence value of | zo | > | z | and here we reject Ho
p-value : two tailed ( double the one tail ) - ha : ( p != -2.86888 ) = 0.00412
hence value of p0.04 > 0.00412, here we reject Ho
ANSWERS
---------------
null, Ho: =40
alternate, H1: !=40
test statistic: -2.86888
critical value: -2.054 , 2.054
decision: reject Ho
p-value: 0.00412

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