TABLE,s using TABLE 3.8 Using Total FST 2 to Designate\"Drunk\" Actual BAC FST D
ID: 3183241 • Letter: T
Question
TABLE,s using TABLE 3.8 Using Total FST 2 to Designate"Drunk" Actual BAC FST Decision Totals Legally Sober Legally Drunk Sober Drunk. 266 Totals 267 296 FST denotes "field sobriety test," which encompasses the One-Leg Stand test you likely know well by now. Let's suppose we have selected one of these 296 drivers at random. Questions (leave answers as fractions) 1. What is the chance of selecting a legally sober driver given you know you have selected a driver the FST said was sober? 2. What is the chance of selecting a legally sober driver given you know you have selected a driver the FST said was drunk? 293Explanation / Answer
1) P(leagally sober | FST said sober) = 2/3
2) P(legally sober | FST said drunk) = 27/293
3) P (FST said drunk | legally sober) = 27/29
4) P (FST said drunk | legally drunk) = 266/267
5) P (FST said drunk) = 293/296
6) P (legally sober) = 29/296
7) (27/29) = (27/293) x (293/296)/(29/296) = 0.931
8) No. These two probabilities are different (Refer question 2 and 3)
9) If the number of drivers the FST said was drunk and the number of drivers that are legally sober are the same, then the selection chances in question 8 would have been the same
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