please do not copy the solution in the textbook solutions because they answered

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please do not copy the solution in the textbook solutions because they answered a wrong question. please try solving the question yourself this is a parallel and series system
I posted this question before but i was given the wrong answer.

0.999 Figure 6.12 Personal computer reliabilities 0,999 3. Consider a more advanced stereo system with component reliabilities a Figure 6.13. Determine the system's reliability. What assumptions are required? e 6.13 ed stereo system 0.995 CD-player 0.99 0.995 Left speaker 0,995 Right speaker -Tuner1 Power supply 0.993 model, 0.96 Tuner 2 0.96 Tuner 3 Amplifier 0.999

Explanation / Answer

The reliability of overall system can be considered in 3 parts:
(i) Subsystem 1 consisting of Power Supply (R1 = 0.993) & Amplifier (R2 = 0.999) i Series:

So,

R(Subsystem 1) = R1 X R2 = 0.993 X 0.999 = 0.992007

(ii) Subsystem 2 consisting of CD Player (R3 = 0.995), Tuner 1 (R4=0.99), Tuner 2 (R5=0.96), Tune 3 (R6=0.96) in parallel.

So,

R(Subsystem 2) = 1 - (1-R3)(1-R4)(1-R5)(1-R6)

                          = 1 - (0.005 X 0.01 X 0.04 X 0.04)

                           = 0.99999992 (zero point seven 9 followed by 2)

(ii) Subsystem 3 consisting of Left speaker (R7 = 0.995) & Right speaker (R8 = 0.995) in parallel.

R(Subsystem3) = 1 - (1-R7)(1-R8)

                        = 1 - 0.0052 = 0.999975 (zero point four 9 followed by 75)

So, Reliability of overall system is the product of the above 3 Subsytems as follows:

RS = 0.992007 X 0.999992 X 0.999975

= 0.99197426

Assumptions:
The redundadat elements are "hot redundacies" and swiching elements have releliability =1

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