The altitude of a triangle is increasing at a rate of 3.000 centimeters minute w

Question

The altitude of a triangle is increasing at a rate of 3.000 centimeters minute while the area of the triangle is increasing at a rate of 1.000 square centimeters minute. At what rate is the base of the triangle changing when the altitude is 9.500 centimeters and the area is 87.000 square centimeters? Note: The "altitude" is the "height" of the triangle in the formula "Area=(l/2)*base*height". Draw yourself a general "representative" triangle and label the base one variable and the altitude (height) another variable. Note that to solve this problem you don't need to know how big nor what shape the triangle really is.

Explanation / Answer

area = 1/2 bh

A = 1/2 bh

87 = 1/2* 9.5*b

b=18.315789473684211

dA/dt = 1/2 ( h db/dt + b dh/dt)

1 = 1/2 ( 9.5 db/dt + 18.31 *3)

db/dt =-5.571578947368421

base changes at rate of 5.5 cm per minure

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