At the reception line of a wedding, the bride, the groom, the best man, the maid
ID: 3197665 • Letter: A
Question
At the reception line of a wedding, the bride, the groom, the best man, the maid of honor, the three ushers, and the three bridesmaids must line up to receive the guests. a) If these individuals can line up in any order, how many arrangements are possible? b) If the groom must be the last in line and the bride must be next to the groom, and the others can line up in any order, how many arrangements are possible? c) If the groom is to be last in line, the bride next to the groom, and males and females are to alternate, how many arrangements are possible? a) If these individuals can line up in any order, how many arrangements are possible? O B. 120 OC. 3,628,800 O D. 5,040 b) If the groom must be the last in line and the bride must be next to the groom, and the others can line up in any order, how many arrangements are possible? O A. 120 OB. 3,628,800 C. 40.320 O D. 576 c) If the groom is to be last in line, the bride next to the groom, and males and females are to alternate, how many arrangements are possible? OA, 576 O B. 24 ?. 36 ? D. 288Explanation / Answer
We have 10 people that needs to be arranged in a line
1.) Number of arrangement possible when no order required =
= 10! = 3,628,800
2.) Since groom is in last of line and bride is next him so both are fixed therefore number of people left to be arranged is 8 so total arrangement possible = 8! = 40,320
3.) Now above two condition are already in place, one more is introduced males and females are to be alternate so now number of females left to be seated =4 and similarly 4 males are left so in remaining 8 seats firstly males are seated alternatively (4! ways) then females are seated (4! ways) ,so total ways = 4!*4! = 24*24 = 576
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