Each person in a random sample of 228 male teenagers and a random sample of 302

Question

Each person in a random sample of 228 male teenagers and a random sample of 302 female teenagers was asked how many hours he or she spent online in a typical week. The sample mean and standard deviation were 15.1 hours and 11.3 hours for males and 14.2 and 11.7 for females. (Use a statistical computer package to calculate the P-value. Use mu_males = mu_females. Round your test to two decimal places, your d down to the nearest whole number and your P-value to three decimal places.) t = 0.9 dt = 486 P = 0.184 Is there enough evidence to show that mean number of hours spent online in a typical week is greater for male teenagers than for female teenagers? Use a 0.05 significance level. Yes No

Explanation / Answer

If the two population variances are not equal

Two-Sample T-Test and CI

Sample N Mean StDev SE Mean
1 228 15.1 11.3 0.75
2 302 14.2 11.7 0.67

Difference = (1) - (2)
Estimate for difference: 0.90
95% lower bound for difference: -0.76
T-Test of difference = 0 (vs >): T-Value = 0.89 P-Value = 0.186 DF = 497

If the two population variances are equal then

Two-Sample T-Test and CI

Sample N Mean StDev SE Mean
1 228 15.1 11.3 0.75
2 302 14.2 11.7 0.67

Difference = (1) - (2)
Estimate for difference: 0.90
95% lower bound for difference: -0.77
T-Test of difference = 0 (vs >): T-Value = 0.89 P-Value = 0.187 DF = 528

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