In Kumquat trees, plant height is determined by 3 genes as in our simplified mod

Question

In Kumquat trees, plant height is determined by 3 genes as in our simplified model of polygenic inheritance. Each locus has a contributing allele and a non-contributing allele. A tree w.th the genotype AABBCC grows to be 100cm tall. The other homozygote grows to be 40cm tall. What is the contribution for each contributing allele? 60cm 50cm 30cm 20cm 10cm If you crossed a 100cm tree with a 40cm tree and then crossed the F_1 to get f_2 generation, what proportion of the F_2 offspring will grow to be 70cm tall? 1/16 20/64 20/128 10/64 1/8 Considering again the F_2 production in question 2, what proportion of the offspring will be 70cm tall or taller? 1/16 15/64 6/64 42/64 1/64 Determine the limit of Kumquat tree height in the offspring of the crosses listed below:

Explanation / Answer

Ques-1). e. 10cm

Reason: Given that the other homozygous is 40 cm tall. This indicates that each dominant allele contributes 10 cm. Thus, each locus contributes 20 cm (each locus contains two alleles).

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